Thursday, April 18, 2013

Maxi Product

maxi carrefour The objective of this coursework is to find the formula that gives the upper limit product of any given crook when split into move. For the set-back part of the coursework I am going to investigate the dissever of a number into two parts, then three parts and into four and five parts. For each number of parts, I am going to come up with a formula that gives the supreme product.
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Starting number 12 PAIR WHICH keep down 12 PRODUCT OF THE PAIR 12, 0 0 11,1 11 10,2 20 9,3 27 8,4 32 7,5 35 6,6 36 5,7 35 4,8 32 3,9 27 2,10 20 1,11 11 0,12 0 TEST FOR THE maxi PRODUCT I will assume my maxi product is in the range between 7,5 and 5,7 because this where the arch is at it’s highest. So, 6.9 ? 5.1=35.19 5.9 ? 6.1=35.99 Neither of these are higher than 36. So for my starting number 12, I have used the pairs 6 and 6 and my maxi product is 36. Starting number 10 PAIR WHICH TOTAL 10 PRODUCT OF THE PA...If you want to get a proficient essay, order it on our website: Ordercustompaper.com

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