maxi carrefour The objective of this coursework is to find the formula that gives the upper limit product of any given crook when split into move. For the set-back part of the coursework I am going to investigate the dissever of a number into two parts, then three parts and into four and five parts. For each number of parts, I am going to come up with a formula that gives the supreme product.
Starting number 12 PAIR WHICH keep down 12 PRODUCT OF THE PAIR 12, 0 0 11,1 11 10,2 20 9,3 27 8,4 32 7,5 35 6,6 36 5,7 35 4,8 32 3,9 27 2,10 20 1,11 11 0,12 0 TEST FOR THE maxi PRODUCT I will assume my maxi product is in the range between 7,5 and 5,7 because this where the arch is at it’s highest. So, 6.9 ? 5.1=35.19 5.9 ? 6.1=35.99 Neither of these are higher than 36. So for my starting number 12, I have used the pairs 6 and 6 and my maxi product is 36. Starting number 10 PAIR WHICH TOTAL 10 PRODUCT OF THE PA...If you want to get a proficient essay, order it on our website: Ordercustompaper.com
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